Table 1. Summary of the experimental categories used in the study.
Group
code
Species
group
Disruptive
camouflage?
Symmetrical
camouflage?
Sex
Sample
size
1
1
No
No
Male
N = 100
2
1
No
No
Female
N = 100
3
1
Yes
No
Male
N = 100
4
1
Yes
No
Female
N = 100
5
1
No
Yes
Male
N = 100
6
1
No
Yes
Female
N = 100
7
1
Yes
Yes
Male
N = 100
8
1
Yes
Yes
Female
N = 100
9
2
No
No
Male
N = 100
10
2
No
No
Female
N = 100
11
2
Yes
No
Male
N = 100
12
2
Yes
No
Female
N = 100
13
2
No
Yes
Male
N = 100
14
2
No
Yes
Female
N = 100
15
2
Yes
Yes
Male
N = 100
16
2
Yes
Yes
Female
N = 100
On Blackboard, there is an Excel file containing these data. Eight columns of data are present in this file. These eight columns of data are as follows:
COUNTER = a simple case ID code (you will not need to use this in any analysis)
SPECIES = a code for species group (species group 1 = 1, species group 2 = 2)
SYMMETRY = whether the moth had symmetrical camouflage (no = 0, yes = 1)
DISRUPT = whether moth had disruptive camouflage (no = 0, yes = 1)
SEX = sex (male =1, female =2)
TIME = survival time in days. This is the number of days the moth survived during the course of the whole experiment.
SURVIVE49 = whether animal survived to 49 days or not (no = 0, yes = 1). This is a binary variable indicating whether the moth survived to 49 days during the experiment, or whether it was killed before 49 days.
GROUPING = a code detailing the species-sex-symmetry-disruptive grouping. This is the same as the first column in Table 1.
One way analysis of ANOVA
Hypothesis
There is no significant difference in survival time among different groups
There is a significant difference in survival time among different groups
Level of significance = 0.05
Calculation with SPSS
ANOVA
survival time in days
Sum of Squares
df
Mean Square
F
Sig.
Between Groups
71615.325
15
4774.355
48.495
.000
Within Groups
155945.809
1584
98.451
Total
227561.133
1599
From the above table it can be seen that in this case the p value is 0 which is less than level of significance, hence it can be concluded that there is a significant difference in survival time among different groups and null hypothesis should be rejected.
Hypothesis
There is no significant difference in survival time among different species
There is a significant difference in survival time among different species
Level of significance = 0.05
Calculation with SPSS
ANOVA
survival time in days
Sum of Squares
df
Mean Square
F
Sig.
Between Groups
27286.630
1
27286.630
217.721
.006
Within Groups
200274.503
1598
125.328
Total
227561.133
1599
Again in case it can be seen that the p value is less than level of significance and we have to reject our null hypothesis and conclude that there is a significant difference in survival time among different species.
Chi square test
Group * survival time in days (Binned) Crosstabulation