STATISTICAL ANALYSIS

Statistical Analysis

Statistical Analysis

Question 1

Statistics

Readings on Successive Days

N

Valid

99

Missing

0

Mean

85.4545

Median

85.0000

Mode

78.00

Std. Deviation

7.21290

Lower Quartiles

75.00

Upper Quartiles

99.00

Percentiles

25

79.0000

50

85.0000

75

91.0000

The shape of the above graph is showing that there is too much fluctuation for readings on successive days as the mean vale of the readings on successive days is 85.45 with the standard deviation of 7.213.

Question 2

Hazards due to Environmental

Lightning

Heat

Rocky trail

Humidity

Rain

Dehydration

Wet trail

Hazards due to Human Factor

Age of kids, their physical abilities and experience

Group of kids

Limited group resources in an emergency

Dan's inexperience

Possible Accident

Lightning strike

Heat exhaustion, heat stroke

Fall



Reducing the Accident Potential

The group can have a better plan for the day in terms of mileage, when to leave camp, rest breaks, lunch breaks, etc.

The group should have better knowledge of the terrain and the appropriateness of the route to the age group of the participants.

More experienced leaders.

The group should have a plan for bail out in case of bad weather.

The trip route should also include an understand of how weather conditions can increase the Accident Potential of a particular section.

Question 3

Model Summary b

Model

R

R Square

Adjusted R Square

Std. Error of the Estimate

Change Statistics

R Square Change

F Change

df 1

df 2

Sig. F Change

1

.263a

.069

-.105

13.74957

.069

.397

3

16

.757

a. Predictors: (Constant), X4, X3, X2

b. Dependent Variable: X1

ANOVA b

Model

Sum of Squares

df

Mean Square

F

Sig.

1

Regression

225.428

3

75.143

.397

.757a

Residual

3024.810

16

189.051

Total

3250.238

19

a. Predictors: (Constant), X4, X3, X2

b. Dependent Variable: X1

The above charts are showing that the significant value of ANOVA table is not less than 0.05 and the value of R is 0.263 and the value of R - square is 6.9 % that means the data is not normally distributed. Therefore, it can be said that the layer thickness is not normally distributed. In addition to this, if the specifications are at 675 ± 45, the process capability will be;

Coefficientsa

Model

Unstandardized Coefficients

Standardized Coefficients

t

Sig.

Collinearity Statistics

B

Std. Error

Beta

Tolerance

VIF

1

(Constant)

861.239

251.821

3.420

.004

X2

.161

.232

.191

.693

.498

.769

1.300

X3

-.249

.278

-.225

-.895

.384

.917

1.090

X4

-.192

.254

-.205

-.754

.462

.785

1.275

a. Dependent Variable: X1

From the above table, it can be said that the beta value ...