2. If dfB = 4 and dfW = 20, using alpha = 0.05, Fcrit = _________.
a. 2.87
b. 3.10
c. 3.74
d. 6.22
3. An investigator conducts an experiment involving the effects of three levels of a drug on memory. Subjects are randomly assigned to one of three conditions. A different drug level is administered in each condition. Memory is measured 10 minutes after each subject receives the drug. The following scores are recorded. The higher the score, the better the memory. Drug Level onetwothree
6914
5713
8915
21319
After conducting a one-way ANOVA of the above data, which of the following is the variability among the group means 15.5 .
ANOVA
VAR00002
Sum of Squares
df
Mean Square
F
Sig.
Between Groups
201.500
2
100.750
15.500
.001
Within Groups
58.500
9
6.500
Total
260.000
11
a.6.50
b.15.5
c.100.75
d.201.5
4. Refer to the drug study. After conducting a one-way ANOVA of the above data, which of the following is the average variance within each of the three groups.
a. 6.50
b. 15.5
c. 100.75
d. 201.5
5. Refer to the drug study. After conducting a one-way ANOVA of the above data, which of the following is the F critical using alpha at 0.05.
a. 3.63
b. 4.26
c. 5.12
d. 4.46
6. If I have four groups, and a total of 40 subjects in the entire experiment, how many within groups degrees of freedom do I have.
a. 39
b. 3
c. 36
d. 28
7. Refer to the drug study. When calculating the total sum of squares, I utilize the following expression: SStotal = 1460 - (120)2/12 which equals 260. The SS between = (21)2/4 + (38)2/4 + (61)2/4 - (120)2/12 which equals 201.5. Based on this information which of the following is the numerator of the average variance within each group.
a. 1460
b. 201.5
c. 120
d. 58.5
8. Refer to the drug study. When calculating the total sum of squares, I utilize the following expression: SStotal = 1460 - (120)2/12 which equals 260. The SS between = (21)2 + (38)2 + (61)2 - (120)2/12 which equals 201.5. Based on this information which of the following is the numerator of the total variance among all the scores.
a. 1460
b. 201.5
c. 120
d. 260.
9. Refer to the drug study Estimate the size of the effect. Using omega squared.
a. 0.5109
b. 0.6698
c. 1.6633
d. 0.7073
? 2 = (SSB-(k-1)MS within)
(SSt+MS within)
? 2
=
100.75
260
+
58.5
? 2
=
100.75
318.5
? 2
=
0.316
10. Refer to drug study. Estimate the size of the effect using Cohen's f.
a. 1.4244
b. 0.6698
c. 1.6633
d. 1.5546
Cohen's FSQRT (k-1)(MSbet-MSwith) knMSwith
Cohen's F
=
SQRT
(2) * (201.5 - 58.5)
260
+
58.5
Cohen's F
=
SQRT
2
143
318.5
Cohen's F
=
SQRT
286.000
Cohen's F
=
16.91
11. A sleep researcher conducts an experiment to determine whether sleep loss affects the ability to maintain sustained attention. Fifteen individuals are randomly divided into the following three groups of 5 subjects each: group 1, which gets the normal amount of sleep (7-8 hours); group 2, which is sleep-deprived for 24 hours; group 3, which is sleep-deprived for 48 hour. And group 4 which is sleep deprived for 72 hours. All four groups are tested on same auditory vigilance task. Subjects are presented with half-second tones spaced at irregular intervals over a 1-hour ...