1. Draw the network diagram (use activity on the node).
Graph 1: Network Diagram (Activity-on-Node)
Refer to “Activity-on-node networks with minimal and maximal time lags and their application to make-to-order production”. (Neumann & Schwindt, 1997)
2. Explain how you determined the timing of activities and the total float
According to the duration of any activity and the relationships between one activity and others, we can calculate the timing of activities (includes earliest start, earliest finish, latest start, latest finish and total float) (Field & Keller, 2007).
Chart 2: The Timing of Activities
Task Number
Predecessor
Lead/ Lag
Duration Optimistic
Duration Expected
Duration Pessimistic
Sim Value
EST
EFT
LST
LFT
Slack
Crit Path
Prob. on CP
Start
0
0
0
-238
-238
-238
Task 1
Start FS
4
15
20
15
0
15
-235
-220
-235
1
0
Task 2
1 FS
-5
5
20
22
20
10
30
-225
-205
-235
1
0
Task 3
2 FS
9
26
30
26
30
56
-205
-179
-235
1
0
Task 4
2 SS
10
4
18
23
18
20
38
-212
-194
-232
1
0
Task 5
4 FS
7
15
17
15
38
53
-194
-179
-232
1
0
Task 6
3,5 FS
5
38
45
38
56
94
-179
-141
-235
1
0
Task 7
6 FS
-5
11
25
30
25
89
114
-146
-121
-235
1
0
Task 8
6 FS
5
5
15
20
15
99
114
-136
-121
-235
1
0
Task 9
6 SS
20
5
18
22
18
76
94
-139
-121
-215
1
0
Task 10
7,8,9 FS
4
30
45
30
114
144
-121
-91
-235
1
0
Task 11
10 FS
5
5
28
39
28
149
177
-86
-58
-235
1
0
Task 12
Start FS
5
140
180
140
0
140
-238
-98
-238
1
1
Task 13
12 FS
-5
7
18
22
18
135
153
-103
-85
-238
1
1
Task 14
13 SS
10
5
20
25
20
145
165
-93
-73
-238
1
1
Task 15
14 FS
5
15
20
15
165
180
-73
-58
-238
1
1
Task 16
11, 15 FS
7
33
60
33
180
213
-58
-25
-238
1
1
Task 17
16 FS
4
8
11
8
213
221
-25
-17
-238
1
1
Task 18
17 FS
4
15
25
15
221
236
-15
0
-236
1
1
Task 19
17 FS
5
17
19
17
221
238
-17
0
-238
1
0
The predecessor and successor relationship and the duration of each activity are known in this case. Earliest start time equals to the earliest finish time of predecessor activity. Earliest finish time equals to the earliest start time plus to the activity duration. Latest finish time equals to the latest start time of successor activity and Latest start time equals to the latest finish time minors the duration. The total float means the difference between earliest start time and the latest start time.
3. Explain how you determined the project duration and the critical path
After all the activities are done, the life circle of project is finished. And that time is the total duration of the project itself. Critical Path Method (CPM) is a kind of model to calculate the critical path in the whole project, which will have the biggest influence to the project total duration. In this case, the Total project duration is 83 days, as the activity Q is finished in that day. The critical path is the process of A-E-F-G-H-I-K-L-M-N-P-Q. If any change occurs in those activities, then the total duration will be change definitely.
4. 4)If the project starts on the Monday 6 August 2012, what is the earliest date it can be completed using a 5 day working week? Assume no other holidays
If the project starts on the Monday 6 August 2012 and the working time is 5 day a week, the whole period of project will be calculate by the equation: TRUNC(83/5)*7+MOD(83/5). The result is 115 day. Then we can know the finish time is Thursday 15 October, 2012.
5. If the following happened what would be the effect on the duration of the whole project? Explain the reasons.
Activity D is delayed 1 day. As activity D is a critical path, so the total duration of project will be delayed for 1 day.
A 1 day delay during activity M. No effect. Activity M has a 67 days' flexibility time.\
A 1 day early finish in activity Q. No effect. Activity Q has an 8 days' flexibility time. So early finish does not have any ...