INFORMATION ANALYSIS

Information Analysis

Information Analysis

Question # 01

What is the equation of the line that passes though the points (2, 1) and (4, 9)?

Solution

For finding an equation, first we have to find the value of slope by using the given points.

The given points are (2, 1) and (4, 9)

Where x1 = 2 and y1 = 1

X2 = 4 and y2 = 9

By using the formula of slope we can find the value of gradient. The slope formula is

m = 9 - 1/ 4 - 2

m = 8 / 2

m = 4

The values of x1, x2, y1 and y2 are the given coordinates that can help to find out the value of slope and the value of slope is 4.

Now we use the point slope formula that will help to evaluate the equation of the line that passes through the points.

Where m is the slope value

Y - 1 = 4(x - 2)

Y - 1 = 4x -8

Y = 4x -8 + 1

Y = 4x -7

Hence the equation that has evaluated by using the given coordinates values is y = 4x-7

Question # 02

x2 - 3x - 1 = 0

Solution

By using the quadratic equation we can solve this given equation and find out the coordinates of x. The formula of quadratic equation is

a = 1, b = -3, c = -1

Putting the above values in the quadratic equation

X = - (-3) ± under root ((-3) ^2 - 4(1) (-1)/2(1)

X = 3 ±Under root (9 +4)/2

X = 3 ± under root (13)/2

Hence the coordinates of this equation cannot be identified because the values are complex, so it's not possible to evaluate the proper values of coordinates.

Question # 03

A sample of 60 access times (to the nearest millisecond) onto a computer system is shown below:

894

892

907

908

902

911

894

909

890

903

897

914

892

889

906

913

886

896

910

909

901

898

904

901

901

898

912

911

889

908

885

886

881

904

881

894

879

901

902

916

907

904

897

911

917

928

917

909

921

925

885

913

921

920

889

895

902

904

906

901

Solution

First we copy the given data on excel sheet and then we can use excel options for finding the grouped frequency table. This will be possible in excel by using

Go to Excel Sheet - Data- Data Analysis- Histogram Option

Through this procedure we can find out the grouped frequency table.

Bin

Frequency

Bin

Frequency

879

1

907

17

886

6

914

13

893

6

900

9

900

9

886

6

907

17

893

6

914

13

921

6

921

6

More

2

More

2

879

1

Bin

Frequency

Cumulative %

Bin

Frequency

Cumulative %

879

1

1.67%

907

17

28.33%

886

6

11.67%

914

13

50.00%

893

6

21.67%

900

9

65.00%

900

9

36.67%

886

6

75.00%

907

17

65.00%

893

6

85.00%

914

13

86.67%

921

6

95.00%

921

6

96.67%

More

2

98.33%

More

2

100.00%

879

1

100.00%

Histogram

Interpretation

The given histogram defines the decline position of the trend line. Through this graph we can easily identify the individual frequency of the given data set.

Question # 04

Below are the preliminary results for a mathematics module.

15

16

0

36

60

47

36

32

0

0

44

45

62

65

70

66

65

50

66

65

0

9

54

28

55

43

18

2

52

19

9

71

52

1

33

39

34

62

27

64

69

66

2

58

58

45

13

58

68

48

58

23

65

56

28

54

67

48

62

67

71

75

8

0

43

73

16

67

9

37

32

0

31

39

9

58

2

71

11

63

73

76

75

72

41

68

50

16

22

7

1

55

46

51

0

18

40

64

0

0

38

18

62

38

55

47

0

0

17

0

45

Solution

Bin

Frequency

Bin

Frequency

0

12

68.4

17

7.6

5

More

13

15.2

8

0

12

22.8

11

60.8

12

30.4

5

22.8

11

38

9

45.6

11

45.6

11

38

9

53.2

8

15.2

8

60.8

12

53.2

8

68.4

17

7.6

5

More

13

30.4

5

10.090909

The estimate mean value of grouped frequency table is 10.09.

1

2

3

4

5

6

7

8

9

10

Mean

15

16

0

36

60

47

36

32

0

0

24.2

44

45

62

65

70

66

65

50

66

65

59.8

0

9

54

28

55

43

18

2

52

19

28

9

71

52

1

33

39

34

62

27

64

39.2

69

66

2

58

58

45

13

58

68

48

48.5

58

23

65

56

28

54

67

48

62

67

52.8

71

75

8

0

43

73

16

67

9

37

39.9

32

0

31

39

9

58

2

71

11

63

31.6

73

76

75

72

41

68

50

16

22

7

50

1

55

46

51

0

18

40

64

0

0

27.5

38

18

62

38

55

47

0

0

17

0

27.5

45

 

 

 

 

 

 

 

 

 

45

Mean

39.5

There is a vast difference between calculated and estimated mean because the values allocation is different in both the cases.

Histogram

Interpretation

The histogram defines the individual and specific counting for all the variables that is used in the data set. The data has arranged in descending order from highest to lowest through this grouped frequency table.

The very low mark that has recorded for students who discontinued for taking the module is 0. The best measure of central tendency is mean because through which we can easily identified the average values of the given data set. Besides mean we can also find median mode because these are also significant measures of central ...