ASSIGNMENT

Assignment for Electronic Instruments

[Student Number]

Assignment for Electronic Instruments

Problem 1

A resistor of 10k? is connected to a 10 V battery. Calculate the current flowing through the resistor and the power dissipated in it.

Current Flowing Through the Resistor

The current flowing through the resistor can be calculated with the help of Ohm's Law. According to this law:

V = I*R

I =

I =

I = 1 mA

Power Dissipated in the Resistor

The power dissipated in the resistor can be calculated with the help of the following formula:

P = V*I

P = 10*0.001

P = 10 mWatt

Problem 2

The power dissipated in a 100? resistor is 150 Watts. Calculate the current through the resistor and the voltage applied to it.

Current through the Resistor

The current flowing through the resistor can be calculated with the help of the following formula:

P = = = = 1.5

I = v1.5

I = 1.22 Amperes

Voltage Applied to the Resistor

The voltage applied to the resistor can be calculated with the help of the following formula:

P = V*I

V =

V =

V = 122.95 Volts

Problem 3

Three resistors of 1 k?, 100? and 330? are connected in series across a voltage source (battery). If the power dissipated in the 100? resistor is 100 mW, calculate the voltage drop across each resistor and the total voltage that must be applied to the series circuit.

To find the required factors, the first requirement is the calculation of current. It can be calculated through the following formula:

0.001

I = 0.031 Amperes

Voltage Drop across 1 K?

The Voltage Drop across 1 K? can be calculated with the help of Ohm's Law. According to this law:

V = I*R

V1 = I*R1

V1 = 0.031*1000

V1 = 31 V

Voltage Drop across 100?

The Voltage Drop across 100? can be calculated with the help of Ohm's Law. According to this law:

V = I*R

V2 = I*R2

V2 = 0.031*100

V2 = 3.1 V

Voltage Drop across 330?

The Voltage Drop across 330? can be calculated with the help of Ohm's Law. According to this law:

V = I*R

V3 = I*R3

V3 = 0.031*330

V3 = 10.23 V

Total Voltage That Must Be Applied To the Series Circuit

Total voltage that must be applied to the series circuit can be calculated by adding the voltages flowing through each resistor.

V = V1 + V2 + V3

V = 31 + 3.1 + 10.23

V = 44.33 Volts

Problem 4

Three resistors of 10?, 100? and 1k? are connected in parallel across a battery. If the power dissipated in the 10? resistor is l0W, calculate the currents flowing in each of the three resistors and the total current flowing from the battery.

To find the required factors, the first requirement is the calculation of applied voltage. It can be calculated through the following formula:

P = = P*R

= 10*10

= 100 Volts

V = 10 Volts

Current Flowing in 10?

I =

I1 =

I1 =

I1 = 1 Amperes

Current Flowing in 100?

I =

I2 =

I2 =

I2 = 0.1 Amperes

Current Flowing in 1k?

I =

I3 =

I3 =

I3 = 0.01 Amperes

Total Current Flowing from the Battery

Total current that must be flowing from the battery can be calculated by ...