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ADVANCED NUMERACY CONCEPTS
Advanced Numeracy Concepts
Advanced Numeracy Concepts
Answer 1) Write the following in expanded notation.
= (-2) x (-2) x (-2) x (-2)
= (5x) x (5x) x (5x)
= (5x) x (x) x (x)
Answer 2) Evaluate the following
= 22 x (-3)3
= 2 x 2 x (-3) x (-3) x (-3)
= 4 x 9 x (-3)
= 36 x (-3)
= -108
= -3 / 62
= -3 / (6 x 6)
= -3 / 36
= -1 / 9
Answer 3) Simplify the following
= b6
= (bxbxbxbxbxb)
= 3(n+p)
= 3n x 3p
= 12f3 x fg
= 12f(3+g)
= 33 x 2 x ab2 x a3 x a3b0
= 27 x 2 x ab2 x a3 x a3b0
= 54 x a3 x ab2 x a3b0
= 54 x a3 x a4b2
= 54 x a7b2
= 54a7b2
= 3st x st6 x 3st2t-6 2s-2 x t5
= 3s2t7 x 3st2t-6 2s-2 x t5
= 9s4t1 x 2s-2t5
= 18s2t6
= (xy)-8 x (xy)3
= (xy)-5
= x-8 / x3
= (x-8) x (x-3)
= x-11
= 3x / 3-y
= 3x x 3y
= 3(x + y)
= x3y-3 / (x-4y2)
= x(3- -4)y(-3-2)
= x7y-5
Answer 4) Simplify the Following.
= 36
(3x3x3x3x3x3)
= ab-12
1/ab12
= x3/4
X0.75
4-6
1/46
= 1/4096
= 2.4x10-4
Answer 5) Write the following as power of power.
= (x3)4
= x12
(4a)b
= 4ab
Answer 6) Write the following as power of power.
= (4a3 x b-2)2
= 4a(3x2) x b(-2x2)
Answer 7) Use the power of power rule to write each of the following as power of product.
= 23a9
= 2(1x3)a(3x3)
= (2a3)3
= 45 x b10
= 4(1x5) x b(2x5)
= (4b2)5
Answer 9) Use the power of quotient rule to write each of the following as power of quotient.
= 36 / c3
= 36c-3
= 2-4j-10 / 36k8
= 2-4j-103-6k-8
Answer 10) Use the power of product, the power of quotient, and the power of a power rules to simplify each of the following.
= (4x4 / y)3
= 4x12 / y3
= 4x12y-3
= ((a2b4c0)3 / a4(b3)2) x (b3c5 / a4)3
= ((a6b12c0) / a4b6) x (b9c15 / a12)
= ((a6b12c0) x a-4b-6) x (b9c15 x a-12)
= ((a2b6c0) x (b9c15 x a-12)
= a-10b15c15
Answer 11) Use the power of product, the power of quotient, and the power of a power rules to simplify each of the following.
= 2xy-3
= 2x / y3
= (a-4 / b3)5
= 1/a4
Answer 12) Simplify the following and then use the negative exponent rule to write with negative exponents (and no positive exponents).
(a) 4-6 / x-8
= x8/46
= x8/4096
(b) = 2/ (b x b x b)
Answer 13) Simplify each ...
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